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Sarma ponovo



1. Izračunajte.

(a) \( 8\sqrt{8} + 2\sqrt{4} = \)

(b) \( -9\sqrt{18} + 8\sqrt{17} - \sqrt{19} = \)

(c) \( \frac{8}{4} \sqrt{8} + \frac{12}{7} \sqrt{6} - \frac{3}{8} \sqrt{5} = \)

(d) \( 3\sqrt{10} - 7\sqrt{12} + 4\sqrt{7} - 1\sqrt{11} = \)

2. Izračunajte.

(a) \( (\sqrt{15})^2 = \)

(b) \( -\left(\frac{4}{8}\right)^2 = \)

(c) \( \sqrt{(-11)^2} = \)

(d) \( (5\sqrt{9})^2 = \)

(e) \( \frac{(-\sqrt{23})^2}{13} = \)

(f) \( 5\left(\sqrt{\frac{3}{7}}\right)^2 = \)

3. Izračunajte i usporedite.

(a) \( \sqrt{12\cdot16} \) _____ \( \sqrt{4} \cdot \sqrt{8} \)

(b) \( \sqrt{75\cdot100} \) _____ \( \sqrt{75} \cdot \sqrt{75} \)

(c) \( \sqrt{\frac{3}{12} \cdot 16} \) _____ \( \sqrt{\frac{2}{12}} \cdot \sqrt{8} \)

(d) \( \sqrt{0.25\cdot3000} \) _____ \( \sqrt{0.46} \cdot \sqrt{10000} \)

4. Izračunajte.

(a) \( \sqrt{50\cdot75} = \)

(b) \( \sqrt{0.38\cdot3\cdot25} = \)

(c) \( \sqrt{18} \cdot \sqrt{6} = \)

(d) \( \sqrt{4} \cdot \sqrt{12} = \)

5. Izračunajte i usporedite.

(a) \( \sqrt{72} \div 8 \) ☐ \( \sqrt{2} \div \sqrt{4} \)

(b) \( \sqrt{9} \div 18 \) ☐ \( \sqrt{8} \div \sqrt{17} \)

(c) \( \sqrt{19} \div 8 \) ☐ \( \sqrt{4} \div \sqrt{8} \)

(d) \( \sqrt{\frac{12}{7}} \div 6 \) ☐ \( \sqrt{\frac{3}{8}} \div \sqrt{5} \)

6. Izračunajte.

(a) \( \sqrt{3} \div 10 = \)

(b) \( \sqrt{7} \div 12 = \)

(c) \( \sqrt{4} \div \sqrt{7} = \)

(d) \( \sqrt{1} \div \sqrt{11} = \)

(e) \( \sqrt{15} \div 4 = \)

(f) \( \sqrt{8} \div -11 = \)

(g) \( \sqrt{5} \div \sqrt{9} \div \sqrt{23} = \)

(h) \( \sqrt{\frac{13}{5}} \div \sqrt{\frac{3}{7}} = \)

7. Izračunajte.

(a) \( \sqrt{\frac{12}{16}} \cdot \sqrt{\frac{4}{8}} \cdot \sqrt{\frac{75}{100}} = \)

(b) \( \sqrt{75} \cdot \sqrt{75} \cdot \sqrt{\frac{3}{12}} \cdot \sqrt{16} = \)

8. Izračunajte.

(a) \( 72 \cdot (-8\sqrt{2}) = \)

(b) \( (4\sqrt{9}) \div 18 = \)

(c) \( \sqrt{8} \cdot (\sqrt{17} + 19) = \)

(d) \( \sqrt{8} \cdot (4\sqrt{8} - \sqrt{12}) = \)

(e) \( \sqrt{7} \cdot (\sqrt{6} - \sqrt{3}) = \)

(f) \( -8\sqrt{5} \cdot (\sqrt{3} + 10\sqrt{7}) = \)

(g) \( (12 + \sqrt{4}) \cdot (\sqrt{7} - 1) = \)

(h) \( (11\sqrt{15} + 4) \cdot (8 - \sqrt{-11}) = \)

(i) \( (\sqrt{5} - \sqrt{9}) \div \sqrt{23} = \)

(j) \( (\sqrt{13} + \sqrt{5} - \sqrt{3}) \div \sqrt{7} = \)

9. Djelomično korjenjujte.

(a) \( \sqrt{12} = \)

(b) \( \sqrt{16} = \)

(c) \( \sqrt{4} = \)

(d) \( \sqrt{8} = \)

(e) \( \sqrt{75} = \)

(f) \( \sqrt{100} = \)

(g) \( \sqrt{\frac{75}{75}} = \)

(h) \( \sqrt{\frac{3}{12}} = \)

10. Djelomično korjenjujte pa izračunajte.

(a) \( \sqrt{16} + 2\sqrt{12} - 8\sqrt{0.25} = \)

(b) \( 3000\sqrt{0.46} - \sqrt{10000} + 50\sqrt{75} = \)

(c) \( \sqrt{0.38} - 3\sqrt{25} - 18\sqrt{6} = \)

(d) \( \frac{4}{12}\sqrt{48} + \frac{3}{9}\sqrt{54} - \sqrt{192} = \)

(e) \( 5\sqrt{56} - (-3\sqrt{63} + \sqrt{35}) + 4\sqrt{700} = \)

(f) \( 1 \cdot (\sqrt{99} + 3\sqrt{88}) - \sqrt{11} = \)

(g) \( \sqrt{6} \cdot (4\sqrt{144} - 2\sqrt{50}) = \)

(h) \( (-4\sqrt{125} - 2\sqrt{360}) \cdot \sqrt{25} = \)

MIle

Ovo je dobro

(a) Tablica
\( E = mc^2 \) za Sophia \( \int_{a}^{b} x^2 \,dx \)
\( a^2 + b^2 = c^2 \) \( \sum_{n=1}^{\infty} \frac{1}{n^2} \)
\( \lim_{x \to \infty} \frac{1}{x} = 0 \) \( f(x) = \frac{- 72}{1 + e^{-x}} \)
(b) \( \sqrt[n]{8 } \) Elijah Sophia