Zmija na bajsu


Otkleni vo:
1. Izračunaj.

(a) \( \left(-\frac{3.50}{2.20}\right) \cdot \left(-\frac{3.50}{2.20}\right) \cdot \left(\frac{1.40}{1.80}\right) \cdot \left(\frac{1.40}{1.80}\right) \)

(b) \( \left(\frac{3.80}{6.40}\right) \cdot \left(\frac{3.80}{6.40}\right) \cdot \frac{1}{6} \cdot \frac{18}{19 \cdot 19} \)

(c) \( \left(-\frac{2.40}{4.30 \cdot 4.30}\right) \cdot \left(-\frac{2.40}{4.30 \cdot 4.30}\right) - \left(-\frac{3.10}{2.90}\right) \cdot \left(-\frac{3.10}{2.90}\right) \)

(d) \( \frac{1}{4} \cdot \left(\frac{1}{2}\right) \cdot \left(\frac{1}{2}\right) - \frac{1}{8 \cdot 8} \)

(e) \( \frac{1}{2} \cdot \frac{1}{2 \cdot 2} \cdot \frac{10 \cdot 10}{20} \)

(f) \( \frac{3}{2.30} \cdot \left(\frac{7.60}{6}\right) \cdot \left(\frac{7.60}{6}\right) \cdot \frac{7}{2.30} \)

(g) \( \left(\frac{6}{2}\right) \cdot \left(\frac{6}{2}\right) \cdot \frac{4}{1} - \frac{13 \cdot 13}{28} \)

(h) \( \frac{-14 \cdot -14}{7} \cdot \frac{1}{1} - \left(\frac{9}{2}\right) \cdot \left(\frac{9}{2}\right) \)

2. Koji od navedenih izraza ima rezultat jednak nuli?

(a) \( 8^2 \cdot 3.50 \cdot 2.20 - 1.40.5^2 \cdot \left(\frac{1}{2}\right)^2 \)
(b) \( 1.80 \cdot \frac{-3.80^2}{6.40} + \left(\frac{6}{3}\right)^2 \cdot 0.2 \)
(c) \( 18 \cdot \frac{-19^2}{2} + \frac{2.40^2}{4.30^2} \cdot \frac{3}{2} \cdot 3.10 \cdot \frac{-2.90^2}{12} \)
(d) \( (-4)^2 - \frac{-1}{2^2} - (-8)^2 \cdot 2^2 + 2^2 \cdot (-10)^2 - \left(\frac{-20}{2}\right)^2 \)

3. Dopuni tablicu.
x 3 2.30 7.60 6 7 2.30
y 6 2 4 1 13 28
z = x² - y²
4. Dopuni tablicu.
a b a² - b² (a - b)² a² + b² (a + b)²
14 7
1 9
2 10
7 3
-2 1
-0.80 -2
5. Izračunaj vrijednost izraza -x² + 3y² za zadane vrijednosti.

(a) \( x = -1, y = 1 \)
(b) \( x = -3, y = 5 \)
(c) \( x = 2, y = 5 \)
(d) \( x = -5, y = -4 \)

6. Izračunaj vrijednost izraza 2a² + b² za zadane vrijednosti.

(a) \( a = 5, b = -1 \)
(b) \( a = 2.70, b = 3 \)
(c) \( a = -1, b = -3 \)
(d) \( a = 1, b = 1.40 \)

3.50 2.20 1.40 Ime1 Ime2 Ime3 0 700 1300 2000

(a) \( \left(-\frac{3.50}{2.20}\right) \cdot \left(-\frac{3.50}{2.20}\right) \cdot \left(\frac{1.40}{1.80}\right) \cdot \left(\frac{1.40}{1.80}\right) \)

(b) \( \left(\frac{3.80}{6.40}\right) \cdot \left(\frac{3.80}{6.40}\right) \cdot \frac{1}{6} \cdot \frac{18}{19 \cdot 19} \)

(c) \( \left(-\frac{2.40}{4.30 \cdot 4.30}\right) \cdot \left(-\frac{2.40}{4.30 \cdot 4.30}\right) - \left(-\frac{3.10}{2.90}\right) \cdot \left(-\frac{3.10}{2.90}\right) \)

(d) \( \frac{1}{4} \cdot \left(\frac{1}{2}\right) \cdot \left(\frac{1}{2}\right) - \frac{1}{8 \cdot 8} \)

(e) \( \frac{1}{2} \cdot \frac{1}{2 \cdot 2} \cdot \frac{10 \cdot 10}{20} \)

(f) \( \frac{3}{2.30} \cdot \left(\frac{7.60}{6}\right) \cdot \left(\frac{7.60}{6}\right) \cdot \frac{7}{2.30} \)

(g) \( \left(\frac{6}{2}\right) \cdot \left(\frac{6}{2}\right) \cdot \frac{4}{1} - \frac{13 \cdot 13}{28} \)

(h) \( \frac{-14 \cdot -14}{7} \cdot \frac{1}{1} - \left(\frac{9}{2}\right) \cdot \left(\frac{9}{2}\right) \)