Zmija na bajsu


Otkleni vo:
1. Izračunaj.

(a) \( \left(-\frac{0.90}{2.80}\right) \cdot \left(-\frac{0.90}{2.80}\right) \cdot \left(\frac{2.90}{3.80}\right) \cdot \left(\frac{2.90}{3.80}\right) \)

(b) \( \left(\frac{9.40}{7.40}\right) \cdot \left(\frac{9.40}{7.40}\right) \cdot \frac{1}{2} \cdot \frac{15}{37 \cdot 37} \)

(c) \( \left(-\frac{4.60}{2.40 \cdot 2.40}\right) \cdot \left(-\frac{4.60}{2.40 \cdot 2.40}\right) - \left(-\frac{6.80}{3.70}\right) \cdot \left(-\frac{6.80}{3.70}\right) \)

(d) \( \frac{1}{7} \cdot \left(\frac{1}{5}\right) \cdot \left(\frac{1}{5}\right) - \frac{1}{4 \cdot 4} \)

(e) \( \frac{1}{2} \cdot \frac{1}{2 \cdot 2} \cdot \frac{8 \cdot 8}{16} \)

(f) \( \frac{1}{2.80} \cdot \left(\frac{3.70}{8}\right) \cdot \left(\frac{3.70}{8}\right) \cdot \frac{1}{3.50} \)

(g) \( \left(\frac{12}{3}\right) \cdot \left(\frac{12}{3}\right) \cdot \frac{8}{5} - \frac{19 \cdot 19}{16} \)

(h) \( \frac{-6 \cdot -6}{4} \cdot \frac{1}{4} - \left(\frac{8}{4}\right) \cdot \left(\frac{8}{4}\right) \)

2. Koji od navedenih izraza ima rezultat jednak nuli?

(a) \( 7^2 \cdot 0.90 \cdot 2.80 - 2.90.5^2 \cdot \left(\frac{1}{2}\right)^2 \)
(b) \( 3.80 \cdot \frac{-9.40^2}{7.40} + \left(\frac{2}{3}\right)^2 \cdot 0.2 \)
(c) \( 15 \cdot \frac{-37^2}{2} + \frac{4.60^2}{2.40^2} \cdot \frac{3}{2} \cdot 6.80 \cdot \frac{-3.70^2}{12} \)
(d) \( (-7)^2 - \frac{-1}{5^2} - (-4)^2 \cdot 2^2 + 2^2 \cdot (-8)^2 - \left(\frac{-16}{2}\right)^2 \)

3. Dopuni tablicu.
x 1 2.80 3.70 8 1 3.50
y 12 3 8 5 19 16
z = x² - y²
4. Dopuni tablicu.
a b a² - b² (a - b)² a² + b² (a + b)²
6 4
4 8
4 7
9 3
-3 -1
-0.20 -2.50
5. Izračunaj vrijednost izraza -x² + 3y² za zadane vrijednosti.

(a) \( x = 1, y = 5 \)
(b) \( x = -6, y = 3 \)
(c) \( x = 3, y = 5 \)
(d) \( x = -6, y = -3 \)

6. Izračunaj vrijednost izraza 2a² + b² za zadane vrijednosti.

(a) \( a = 2, b = -1 \)
(b) \( a = 7.40, b = 5 \)
(c) \( a = -2, b = -1 \)
(d) \( a = 0.80, b = 0.80 \)

0.90 2.80 2.90 Ime1 Ime2 Ime3 0 700 1300 2000

(a) \( \left(-\frac{0.90}{2.80}\right) \cdot \left(-\frac{0.90}{2.80}\right) \cdot \left(\frac{2.90}{3.80}\right) \cdot \left(\frac{2.90}{3.80}\right) \)

(b) \( \left(\frac{9.40}{7.40}\right) \cdot \left(\frac{9.40}{7.40}\right) \cdot \frac{1}{2} \cdot \frac{15}{37 \cdot 37} \)

(c) \( \left(-\frac{4.60}{2.40 \cdot 2.40}\right) \cdot \left(-\frac{4.60}{2.40 \cdot 2.40}\right) - \left(-\frac{6.80}{3.70}\right) \cdot \left(-\frac{6.80}{3.70}\right) \)

(d) \( \frac{1}{7} \cdot \left(\frac{1}{5}\right) \cdot \left(\frac{1}{5}\right) - \frac{1}{4 \cdot 4} \)

(e) \( \frac{1}{2} \cdot \frac{1}{2 \cdot 2} \cdot \frac{8 \cdot 8}{16} \)

(f) \( \frac{1}{2.80} \cdot \left(\frac{3.70}{8}\right) \cdot \left(\frac{3.70}{8}\right) \cdot \frac{1}{3.50} \)

(g) \( \left(\frac{12}{3}\right) \cdot \left(\frac{12}{3}\right) \cdot \frac{8}{5} - \frac{19 \cdot 19}{16} \)

(h) \( \frac{-6 \cdot -6}{4} \cdot \frac{1}{4} - \left(\frac{8}{4}\right) \cdot \left(\frac{8}{4}\right) \)

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