$$ \begin{flalign*} & \textbf{Aufgabe 1 } & \\ a) \hspace{1cm} & \6 X + 6 = -12 \\ b) \hspace{1cm} & \14 X + 3 = -30 \\ c) \hspace{1cm} & \15 X + 12 + -9 = 10 - 12 X \\ d) \hspace{1cm} & \-12 X + 3 = -19 \\ e) \hspace{1cm} & \6 X + 3 -19 = 6 X + 3 -19 \\ f) \hspace{1cm} & \13 X + 3 = -19 + -19 X \\ h) \hspace{1cm} & \6 X + 3 + 2X - -19 = 6 X + 3 -19 X + 6 \\ & \textbf{Aufgabe 2} & \\ a) \hspace{1cm} & \-12 X^{2}-\frac{1}{ 3 } X^{3} = 0 \\ b) \hspace{1cm} & \6 X^{2}-\frac{1}{ 6 } X^{2} = 0\\ c) \hspace{1cm} & \ binom{21}{x}\sum_{x}^{x+12} ( X+2X - 6 ) \\ d) \hspace{1cm} & \ X^{3} - 6 X - 6 + -12 X^{2}-\frac{1}{ 3 } x^{2} = 0 \\ e) \hspace{1cm} & \ e) \binom{21}{x}\sum_{x}^{x+12} ( X+2X - 6 ) \\ & \textbf{Aufgabe 3} & \\ \left( 6 a-b\right)^2 + \left(b- 2 \right)^2 + \left( - 6 c - 6 \right)^2 = 0 \\ \left( 3 a-b\right)^2 + \left(b- -30 \right)^2 + \left( - 15 c - 12 \right)^2 = 0 \\ \left( -9 a-b\right)^2 + \left(b- 14 \right)^2 + \left( - 12 c - 12 \right)^2 = 0 \\ \left( -9 a-b\right)^2 + \left(b- 14 \right)^2 + \left( - 12 c - 12 \right)^2 = 0 \\ \end{flalign*} $$