$$ \begin{flalign*} & \textbf{Aufgabe 1 } & \a) \hspace{1cm} & \6 X + 6 = -12 \b) \hspace{1cm} & \5 X + 3 = 26 \\ c) \hspace{1cm} & \3 X + 3 + 3 = 10 - 3 X \d) \hspace{1cm} & \-12 X + 3 = 28 \\ e) \hspace{1cm} & \4 X + 3 28 = 4 X + 3 28 \f) \hspace{1cm} & \1 X + 3 = 28 + 28 X \\ h) \hspace{1cm} & \4 X + 3 + 2X - 28 = 4 X + 3 28 X + 6 \ & \textbf{Aufgabe 2} & \a) \hspace{1cm} & \-12 X^{2}-\frac{1}{ 3 } X^{3} = 0 \b) \hspace{1cm} & \6 X^{2}-\frac{1}{ 6 } X^{2} = 0\\ c) \hspace{1cm} & \ binom{21}{x}\sum_{x}^{x+12} ( X+2X - 6 ) \d) \hspace{1cm} & \ X^{3} - 6 X - 6 + -12 X^{2}-\frac{1}{ 3 } x^{2} = 0 \\ e) \hspace{1cm} & \ e) \binom{21}{x}\sum_{x}^{x+12} ( X+2X - 6 ) \ & \textbf{Aufgabe 3} & \\left( 6 a-b\right)^2 + \left(b- 16 \right)^2 + \left( - 6 c - 6 \right)^2 = 0 \\left( 3 a-b\right)^2 + \left(b- 26 \right)^2 + \left( - 3 c - 3 \right)^2 = 0 \\left( 3 a-b\right)^2 + \left(b- 5 \right)^2 + \left( - 3 c - 3 \right)^2 = 0 \\left( 3 a-b\right)^2 + \left(b- 5 \right)^2 + \left( - 3 c - 3 \right)^2 = 0 \ \end{flalign*} $$